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x in (-oo:+oo)
x^(2/5)+x^(1/5)-6 = 0
t_1 = x^(1/5)
1*t_1^2+1*t_1^1-6 = 0
t_1^2+t_1-6 = 0
DELTA = 1^2-(-6*1*4)
DELTA = 25
DELTA > 0
t_1 = (25^(1/2)-1)/(1*2) or t_1 = (-25^(1/2)-1)/(1*2)
t_1 = 2 or t_1 = -3
t_1 = -3
x^(1/5)+3 = 0
1*x^(1/5) = -3 // : 1
x^(1/5) = -3
( -3 < 0 i 1/5 in (0:1) ) => x naleu017Cy do O
t_1 = 2
x^(1/5)-2 = 0
1*x^(1/5) = 2 // : 1
x^(1/5) = 2
x^(1/5) = 2 // ^ 5
x = 32
x = 32
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